100c^2-120c+36=0

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Solution for 100c^2-120c+36=0 equation:


Simplifying
100c2 + -120c + 36 = 0

Reorder the terms:
36 + -120c + 100c2 = 0

Solving
36 + -120c + 100c2 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '4'.
4(9 + -30c + 25c2) = 0

Factor a trinomial.
4((3 + -5c)(3 + -5c)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(3 + -5c)' equal to zero and attempt to solve: Simplifying 3 + -5c = 0 Solving 3 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -5c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -5c = 0 + -3 -5c = 0 + -3 Combine like terms: 0 + -3 = -3 -5c = -3 Divide each side by '-5'. c = 0.6 Simplifying c = 0.6

Subproblem 2

Set the factor '(3 + -5c)' equal to zero and attempt to solve: Simplifying 3 + -5c = 0 Solving 3 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -5c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -5c = 0 + -3 -5c = 0 + -3 Combine like terms: 0 + -3 = -3 -5c = -3 Divide each side by '-5'. c = 0.6 Simplifying c = 0.6

Solution

c = {0.6, 0.6}

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